Вычислите: $\frac{5}{9} - \frac{2}{9}$

1. Вычисли: * $$\frac{5}{9} - \frac{2}{9} = \frac{5-2}{9} = \frac{3}{9} = \frac{1}{3}$$ * $$\frac{4}{12} + \frac{1}{12} = \frac{4+1}{12} = \frac{5}{12}$$ * $$\frac{17}{20} - \frac{13}{20} = \frac{17-13}{20} = \frac{4}{20} = \frac{1}{5}$$ * $$\frac{19}{20} - \frac{9}{20} = \frac{19-9}{20} = \frac{10}{20} = \frac{1}{2}$$ * $$\frac{15}{22} + \frac{2}{22} = \frac{15+2}{22} = \frac{17}{22}$$ * $$\frac{5}{33} + \frac{8}{33} = \frac{5+8}{33} = \frac{13}{33}$$ * $$\frac{17}{150} + \frac{13}{150} = \frac{17+13}{150} = \frac{30}{150} = \frac{1}{5}$$ * $$\frac{78}{100} - \frac{27}{100} = \frac{78-27}{100} = \frac{51}{100}$$ * $$\frac{43}{44} - \frac{21}{44} = \frac{43-21}{44} = \frac{22}{44} = \frac{1}{2}$$ 2. Выполните действия: * $$8\frac{3}{7} - 2\frac{1}{7} = (8-2) + (\frac{3}{7} - \frac{1}{7}) = 6 + \frac{2}{7} = 6\frac{2}{7}$$ * $$5\frac{6}{8} - 3\frac{2}{8} = (5-3) + (\frac{6}{8} - \frac{2}{8}) = 2 + \frac{4}{8} = 2 + \frac{1}{2} = 2\frac{1}{2}$$ * $$7\frac{3}{11} - \frac{2}{11} = 7 + (\frac{3}{11} - \frac{2}{11}) = 7 + \frac{1}{11} = 7\frac{1}{11}$$ * $$6\frac{8}{23} - \frac{12}{23} = 5 + 1 + \frac{8}{23} - \frac{12}{23} = 5 + \frac{23}{23} + \frac{8}{23} - \frac{12}{23} = 5 + \frac{31}{23} - \frac{12}{23} = 5 + \frac{19}{23} = 5\frac{19}{23}$$ * $$5\frac{7}{9} + 3\frac{4}{9} = (5+3) + (\frac{7}{9} + \frac{4}{9}) = 8 + \frac{11}{9} = 8 + 1\frac{2}{9} = 9\frac{2}{9}$$ * $$12\frac{1}{10} + 3\frac{7}{10} = (12+3) + (\frac{1}{10} + \frac{7}{10}) = 15 + \frac{8}{10} = 15 + \frac{4}{5} = 15\frac{4}{5}$$ * $$10\frac{3}{5} + 6\frac{4}{5} = (10+6) + (\frac{3}{5} + \frac{4}{5}) = 16 + \frac{7}{5} = 16 + 1\frac{2}{5} = 17\frac{2}{5}$$ * $$8\frac{3}{9} + 1\frac{7}{9} = (8+1) + (\frac{3}{9} + \frac{7}{9}) = 9 + \frac{10}{9} = 9 + 1\frac{1}{9} = 10\frac{1}{9}$$ * $$12\frac{7}{8} + 3\frac{7}{8} = (12+3) + (\frac{7}{8} + \frac{7}{8}) = 15 + \frac{14}{8} = 15 + 1\frac{6}{8} = 15 + 1\frac{3}{4} = 16\frac{3}{4}$$ * $$15 - 2\frac{3}{5} = 14\frac{5}{5} - 2\frac{3}{5} = (14-2) + (\frac{5}{5} - \frac{3}{5}) = 12 + \frac{2}{5} = 12\frac{2}{5}$$ * $$19 - 5\frac{6}{13} = 18\frac{13}{13} - 5\frac{6}{13} = (18-5) + (\frac{13}{13} - \frac{6}{13}) = 13 + \frac{7}{13} = 13\frac{7}{13}$$ * $$10\frac{3}{7} - 4\frac{5}{7} = 9\frac{7}{7} + \frac{3}{7} - 4\frac{5}{7} = 9\frac{10}{7} - 4\frac{5}{7} = (9-4) + (\frac{10}{7} - \frac{5}{7}) = 5 + \frac{5}{7} = 5\frac{5}{7}$$