Выполните действия в примерах (с 1 по 10)

1. $19\frac{1}{2}:(3\frac{3}{4}-1\frac{1}{2})-\frac{111}{200}:\frac{3}{20} = \frac{39}{2}:(\frac{15}{4}-\frac{6}{4})-\frac{111}{200} \cdot \frac{20}{3} = \frac{39}{2}:\frac{9}{4}-\frac{37}{10} = \frac{39}{2} \cdot \frac{4}{9}-3.7 = \frac{13 \cdot 2}{3}-3.7 = \frac{26}{3}-3.7 = 8\frac{2}{3}-3\frac{7}{10} = 8\frac{20}{30}-3\frac{21}{30} = 4\frac{29}{30}$ 2. $91:\frac{2}{5}:\frac{3}{5}+3\frac{3}{25}:\frac{12}{25}-\frac{6}{25} = 91 \cdot \frac{5}{2} \cdot \frac{5}{3}+\frac{78}{25} \cdot \frac{25}{12}-\frac{6}{25} = \frac{2275}{6}+\frac{13}{2}-0.24 = 379\frac{1}{6}+6\frac{1}{2}-0.24 = 385\frac{2}{3}-0.24 = 385\frac{200}{300}-\frac{72}{300} = 385\frac{128}{300} = 385\frac{32}{75}$ 3. $(30\frac{4}{5}+27\frac{3}{5}):\frac{9}{10}+(31\frac{16}{25}-12\frac{6}{25}):\frac{2}{3} = 58\frac{7}{5} \cdot \frac{10}{9}+19\frac{10}{25} \cdot \frac{3}{2} = \frac{297}{5} \cdot \frac{10}{9}+\frac{485}{25} \cdot \frac{3}{2} = 33 \cdot 2+\frac{97 \cdot 3}{5 \cdot 2} = 66+29.1 = 95.1$ 4. $(6\frac{7}{20}-1\frac{2}{15}) \cdot 1\frac{1}{4}+(\frac{7}{10}+\frac{7}{20}) \cdot \frac{4}{7} = (6\frac{21}{60}-1\frac{8}{60}) \cdot \frac{5}{4}+\frac{21}{20} \cdot \frac{4}{7} = 5\frac{13}{60} \cdot \frac{5}{4}+\frac{3}{5} = \frac{313}{60} \cdot \frac{5}{4}+0.6 = \frac{313}{48}+0.6 = 6\frac{25}{48}+\frac{3}{5} = 6\frac{125+144}{240} = 7\frac{29}{240}$ 5. (\frac{4}{3} - \frac{2}{9} : \frac{5}{3}) \cdot \frac{2}{9} + (2\frac{1}{7} + 1\frac{2}{3}) = (\frac{4}{3} - \frac{2}{15}) \cdot \frac{2}{9} + (2\frac{3}{21} + 1\frac{14}{21}) = \frac{18}{15} \cdot \frac{2}{9} + 3\frac{17}{21} = \frac{2}{5} \cdot \frac{2}{3} + 3\frac{17}{21} = \frac{4}{15} + 3\frac{17}{21} = \frac{28+85}{105} + 3 = 4\frac{8}{105}$ 6. $(15\frac{1}{8}-8\frac{5}{18}) \cdot \frac{4}{27}-6\frac{1}{21}:\frac{2}{5} = (15\frac{9}{72}-8\frac{20}{72}) \cdot \frac{4}{27}-\frac{127}{21} \cdot \frac{5}{2} = 6\frac{61}{72} \cdot \frac{4}{27}-\frac{635}{42} = \frac{493}{72} \cdot \frac{4}{27}-15\frac{5}{42} = \frac{493}{486}-15\frac{5}{42} = 1\frac{7}{486}-15\frac{5}{42} = -14\frac{271}{2430}$ (с округлением) 7. $8\frac{1}{4}:\frac{1}{10}-(\frac{3}{5}-2\frac{4}{5}:\frac{3}{7}) = 82.5-(0.6-\frac{14}{5} \cdot \frac{7}{3}) = 82.5-(0.6-\frac{98}{15}) = 82.5-0.6+6\frac{8}{15} = 81.9+6\frac{8}{15} = 81\frac{9}{10}+6\frac{8}{15} = 87\frac{27+16}{30} = 88\frac{13}{30}$ 8. $(\frac{1}{6}:\frac{1}{3}-\frac{1}{3}:\frac{1}{5}) \cdot (\frac{1}{6}+\frac{1}{5}) \cdot 3 = (\frac{1}{2}-\frac{5}{3}) \cdot \frac{11}{30} \cdot 3 = (\frac{3-10}{6}) \cdot \frac{11}{10} = -\frac{7}{6} \cdot \frac{11}{10} = -\frac{77}{60} = -1\frac{17}{60}$ 9. $4\frac{3}{5}:\frac{9}{10}+3\frac{1}{2}:\frac{1}{8}-1\frac{1}{5}:\frac{5}{8} = \frac{23}{5} \cdot \frac{10}{9}+\frac{7}{2} \cdot 8-\frac{6}{5} \cdot \frac{8}{5} = \frac{46}{9}+28-\frac{48}{25} = 5\frac{1}{9}+28-1\frac{23}{25} = 33\frac{1}{9}-1\frac{23}{25} = 31\frac{25-207}{225} = 31\frac{43}{225}$ 10. $20-19\frac{1}{2}:(\frac{2}{3}-\frac{3}{4}:\frac{5}{3}) = 20-\frac{39}{2}:(\frac{2}{3}-\frac{3}{4} \cdot \frac{3}{5}) = 20-\frac{39}{2}:(\frac{2}{3}-\frac{9}{20}) = 20-\frac{39}{2}:(\frac{40-27}{60}) = 20-\frac{39}{2} \cdot \frac{60}{13} = 20-3 \cdot 30 = -70$