Выполните действия с обыкновенными дробями: 1) 2 1/2 * 48 - 3 2/3 : 1/18 + 5 5/12 : 7/36; 2) 13 1/2 : 1 1/3 + 16 1/2 * 1 5/11 + 19 1/4 : 4/25; 3) (3 1/2 - 2 2/3 + 5 5/6 + 4 3/5) * 24; 4) (5 3/8 + 18 1/2 - 7 5/24) : 16 2/3; 5) (12 5/12 + 1 2/3 - 3 5/6 + 2 3/4) : (2 1/2 * 2/5 - 7/9); 6) 48 3/5 : 6 3/4 * 5/12 - 2 5/6 + 1 75/94 * (1 1/2 * 1/3 - 13 : 26).

1. $2\frac{1}{2} \cdot 48 - 3\frac{2}{3} : \frac{1}{18} + 5\frac{5}{12} : \frac{7}{36} = \frac{5}{2} \cdot 48 - \frac{11}{3} \cdot 18 + \frac{65}{12} \cdot \frac{36}{7} = 120 - 66 + \frac{65 \cdot 3}{7} = 54 + \frac{195}{7} = 54 + 27\frac{6}{7} = 81\frac{6}{7}$ 2. $13\frac{1}{2} : 1\frac{1}{3} + 16\frac{1}{2} \cdot 1\frac{5}{11} + 19\frac{1}{4} : \frac{4}{25} = \frac{27}{2} \cdot \frac{3}{4} + \frac{33}{2} \cdot \frac{16}{11} + \frac{77}{4} \cdot \frac{25}{4} = \frac{81}{8} + 24 + \frac{1925}{16} = 10\frac{1}{8} + 24 + 120\frac{5}{16} = 154 + \frac{2}{16} + \frac{5}{16} = 154\frac{7}{16}$ 3. $(3\frac{1}{2} - 2\frac{2}{3} + 5\frac{5}{6} + 4\frac{3}{5}) \cdot 24 = (\frac{7}{2} - \frac{8}{3} + \frac{35}{6} + \frac{23}{5}) \cdot 24 = (\frac{105 - 80 + 175 + 138}{30}) \cdot 24 = \frac{338}{30} \cdot 24 = \frac{169}{15} \cdot 24 = \frac{169 \cdot 8}{5} = \frac{1352}{5} = 270\frac{2}{5} = 270,4$ 4. $(5\frac{3}{8} + 18\frac{1}{2} - 7\frac{5}{24}) : 16\frac{2}{3} = (5\frac{9}{24} + 18\frac{12}{24} - 7\frac{5}{24}) : \frac{50}{3} = 16\frac{16}{24} : \frac{50}{3} = 16\frac{2}{3} : \frac{50}{3} = \frac{50}{3} : \frac{50}{3} = 1$ 5. $(12\frac{5}{12} + 1\frac{2}{3} - 3\frac{5}{6} + 2\frac{3}{4}) : (2\frac{1}{2} \cdot \frac{2}{5} - \frac{7}{9}) = (12\frac{5}{12} + 1\frac{8}{12} - 3\frac{10}{12} + 2\frac{9}{12}) : (\frac{5}{2} \cdot \frac{2}{5} - \frac{7}{9}) = 13\frac{0}{12} : (1 - \frac{7}{9}) = 13 : \frac{2}{9} = 13 \cdot \frac{9}{2} = \frac{117}{2} = 58\frac{1}{2} = 58,5$ 6. $48\frac{3}{5} : 6\frac{3}{4} \cdot \frac{5}{12} - 2\frac{5}{6} + 1\frac{75}{94} \cdot (1\frac{1}{2} \cdot \frac{1}{3} - 13 : 26) = \frac{243}{5} \cdot \frac{4}{27} \cdot \frac{5}{12} - 2\frac{5}{6} + \frac{169}{94} \cdot (\frac{3}{2} \cdot \frac{1}{3} - 0,5) = (9 \cdot \frac{4}{12}) - 2\frac{5}{6} + \frac{169}{94} \cdot (0,5 - 0,5) = 3 - 2\frac{5}{6} + 0 = \frac{1}{6}$