Выполните действия с обыкновенными дробями: 1) 6 - 2 7/8; 2) 5 1/3 + 2 3/15; 3) 9 5/6 - 3...

1) $6 - 2\frac{7}{8} = 5\frac{8}{8} - 2\frac{7}{8} = 3\frac{1}{8}$ 2) $5\frac{1}{3} + 2\frac{3}{15} = 5\frac{5}{15} + 2\frac{3}{15} = 7\frac{8}{15}$ 3) $9\frac{5}{6} - 3 = 6\frac{5}{6}$ 4) $7\frac{1}{4} - 3\frac{3}{5} = 7\frac{5}{20} - 3\frac{12}{20} = 6\frac{25}{20} - 3\frac{12}{20} = 3\frac{13}{20}$ 5) $2\frac{8}{14} + 6\frac{18}{21} = 2\frac{4}{7} + 6\frac{6}{7} = 8\frac{10}{7} = 9\frac{3}{7}$ 6) $10 - 4\frac{2}{5} = 9\frac{5}{5} - 4\frac{2}{5} = 5\frac{3}{5}$ 7) $8\frac{1}{9} - 5\frac{5}{6} = 8\frac{2}{18} - 5\frac{15}{18} = 7\frac{20}{18} - 5\frac{15}{18} = 2\frac{5}{18}$ 8) $1\frac{3}{10} + 3\frac{2}{5} = 1\frac{3}{10} + 3\frac{4}{10} = 4\frac{7}{10}$ 9) $9\frac{1}{3} - 5\frac{2}{7} = 9\frac{7}{21} - 5\frac{6}{21} = 4\frac{1}{21}$ 10) $4\frac{2}{3} - 1\frac{1}{6} = 4\frac{4}{6} - 1\frac{1}{6} = 3\frac{3}{6} = 3\frac{1}{2}$ 11) $6\frac{2}{7} + 10 = 16\frac{2}{7}$ 12) $7\frac{11}{16} + 2\frac{13}{24} = 7\frac{33}{48} + 2\frac{26}{48} = 9\frac{59}{48} = 10\frac{11}{48}$ 13) $12 - 5\frac{13}{18} = 11\frac{18}{18} - 5\frac{13}{18} = 6\frac{5}{18}$ 14) $10\frac{18}{25} - 8 = 2\frac{18}{25}$ 15) $8\frac{11}{20} + 5\frac{13}{24} = 8\frac{66}{120} + 5\frac{65}{120} = 13\frac{131}{120} = 14\frac{11}{120}$ 16) $9\frac{17}{24} - 7 = 2\frac{17}{24}$ 17) $9 - 7\frac{18}{20} = 8\frac{20}{20} - 7\frac{18}{20} = 1\frac{2}{20} = 1\frac{1}{10}$ 18) $12\frac{3}{7} + 4\frac{11}{9} = 12\frac{3}{7} + 5\frac{2}{9} = 17\frac{27}{63} + \frac{14}{63} = 17\frac{41}{63}$ 19) $6\frac{11}{20} + 4\frac{7}{15} = 6\frac{33}{60} + 4\frac{28}{60} = 10\frac{61}{60} = 11\frac{1}{60}$ 20) $5\frac{13}{16} + 3 = 8\frac{13}{16}$ 21) $10\frac{1}{18} - 4\frac{2}{3} = 10\frac{1}{18} - 4\frac{12}{18} = 9\frac{19}{18} - 4\frac{12}{18} = 5\frac{7}{18}$ 22) $8 - 1\frac{5}{6} = 7\frac{6}{6} - 1\frac{5}{6} = 6\frac{1}{6}$ 23) $7\frac{12}{16} - 4 = 3\frac{12}{16} = 3\frac{3}{4}$ 24) $2\frac{5}{6} + 1\frac{3}{4} = 2\frac{10}{12} + 1\frac{9}{12} = 3\frac{19}{12} = 4\frac{7}{12}$