1. Найдите значение выражения (4 - y)^2 - y(y + 1) при y = -1/9.

1. $(4 - y)^2 - y(y + 1) = 16 - 8y + y^2 - y^2 - y = 16 - 9y$. При $y = -\frac{1}{9}$: $16 - 9 \cdot (-\frac{1}{9}) = 16 + 1 = 17$. 2. $(a - 3)^2 - 6(2 - a) = a^2 - 6a + 9 - 12 + 6a = a^2 - 3$. При $a = 0,5$: $(0,5)^2 - 3 = 0,25 - 3 = -2,75$. 3. $9(2d + 1) - (d + 9)(9 + d) = 18d + 9 - (d^2 + 18d + 81) = 18d + 9 - d^2 - 18d - 81 = -d^2 - 72$. При $d = 10$: $-100 - 72 = -172$. 4. $x(x + 14) - (7 + x)(x - 7) = x^2 + 14x - (x^2 - 49) = 14x + 49$. При $x = -\frac{3}{7}$: $14 \cdot (-\frac{3}{7}) + 49 = -6 + 49 = 43$. 5. $(y - 4)^2 - (6 + y)(y - 6) = y^2 - 8y + 16 - (y^2 - 36) = y^2 - 8y + 16 - y^2 + 36 = -8y + 52$. При $y = -\frac{7}{8}$: $-8 \cdot (-\frac{7}{8}) + 52 = 7 + 52 = 59$. 6. $x(x + 6) - (x + 3)(x - 3) = x^2 + 6x - (x^2 - 9) = 6x + 9$. При $x = -\frac{19}{3}$: $6 \cdot (-\frac{19}{3}) + 9 = -38 + 9 = -29$. 7. $x(x - 16) - (x + 8)(x - 8) = x^2 - 16x - (x^2 - 64) = -16x + 64$. При $x = \frac{19}{8}$: $-16 \cdot \frac{19}{8} + 64 = -38 + 64 = 26$. 8. $x - \frac{x}{7} = \frac{15}{7} \implies \frac{6x}{7} = \frac{15}{7} \implies 6x = 15 \implies x = 2,5$. 9. $8 - 5(8 + 3x) = 13 \implies 8 - 40 - 15x = 13 \implies -32 - 15x = 13 \implies -15x = 45 \implies x = -3$. 10. $2x - 3(3x + 1) = 11 \implies 2x - 9x - 3 = 11 \implies -7x = 14 \implies x = -2$. 11. $-4x = 15 - 3(3x - 5) \implies -4x = 15 - 9x + 15 \implies 5x = 30 \implies x = 6$. 12. $7 - 3(5x - 3) = -11x \implies 7 - 15x + 9 = -11x \implies 16 = 4x \implies x = 4$. 13. $15 - 4(7 - x) = 11 \implies 15 - 28 + 4x = 11 \implies -13 + 4x = 11 \implies 4x = 24 \implies x = 6$. 14. $6x - 8 = 5x - 3(x - 4) \implies 6x - 8 = 5x - 3x + 12 \implies 6x - 8 = 2x + 12 \implies 4x = 20 \implies x = 5$. 15. $16 + 6x = 5(1 - 2x) - 13 \implies 16 + 6x = 5 - 10x - 13 \implies 16 + 6x = -10x - 8 \implies 16x = -24 \implies x = -1,5$.