Вопрос:

Решите: 2 1/3 : (5/8 - 8/3) + 2 * 1 3/7.

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Ответ ассистента

Давай решим эти примеры по порядку. 1) $2 \frac{1}{3} : (\frac{5}{8} - \frac{8}{3}) + 2 \cdot 1 \frac{3}{7} = \frac{7}{3} : (\frac{15}{24} - \frac{64}{24}) + 2 \cdot \frac{10}{7} = \frac{7}{3} : (-\frac{49}{24}) + \frac{20}{7} = \frac{7}{3} \cdot (-\frac{24}{49}) + \frac{20}{7} = -\frac{8}{7} + \frac{20}{7} = \frac{12}{7} = 1 \frac{5}{7}$. 2) $\frac{3}{4} + 3 \frac{3}{5} \cdot (\frac{5}{18} - \frac{7}{24}) - \frac{1}{5} = \frac{3}{4} + \frac{18}{5} \cdot (\frac{20}{72} - \frac{21}{72}) - \frac{1}{5} = \frac{3}{4} + \frac{18}{5} \cdot (-\frac{1}{72}) - \frac{1}{5} = \frac{3}{4} - \frac{1}{20} - \frac{1}{5} = \frac{15}{20} - \frac{1}{20} - \frac{4}{20} = \frac{10}{20} = 0,5$. 3) $\frac{5}{6} + \frac{10}{9} : (3 - 1 \frac{17}{21}) - 1 \frac{11}{30} = \frac{5}{6} + \frac{10}{9} : (3 - \frac{38}{21}) - \frac{41}{30} = \frac{5}{6} + \frac{10}{9} : (\frac{63-38}{21}) - \frac{41}{30} = \frac{5}{6} + \frac{10}{9} : \frac{25}{21} - \frac{41}{30} = \frac{5}{6} + \frac{10}{9} \cdot \frac{21}{25} - \frac{41}{30} = \frac{5}{6} + \frac{14}{15} - \frac{41}{30} = \frac{25}{30} + \frac{28}{30} - \frac{41}{30} = \frac{12}{30} = 0,4$. 4) $2 \frac{1}{2} + \frac{9}{16} \cdot 1 \frac{5}{27} - 3 \frac{3}{7} : \frac{27}{28} = 2,5 + \frac{9}{16} \cdot \frac{32}{27} - \frac{24}{7} \cdot \frac{28}{27} = 2,5 + \frac{2}{3} - \frac{32}{9} = 2,5 + \frac{6}{9} - \frac{32}{9} = 2,5 - \frac{26}{9} = \frac{5}{2} - \frac{26}{9} = \frac{45-52}{18} = -\frac{7}{18}$. 5) $\frac{4}{3} + (-8 \frac{1}{9} + \frac{8}{5} \cdot 3 \frac{1}{8}) : \frac{7}{6} = \frac{4}{3} + (-\frac{73}{9} + \frac{8}{5} \cdot \frac{25}{8}) : \frac{7}{6} = \frac{4}{3} + (-\frac{73}{9} + 5) : \frac{7}{6} = \frac{4}{3} + (-\frac{73}{9} + \frac{45}{9}) : \frac{7}{6} = \frac{4}{3} + (-\frac{28}{9}) \cdot \frac{6}{7} = \frac{4}{3} - \frac{8}{3} = -\frac{4}{3} = -1 \frac{1}{3}$. 6) $\frac{16}{15} : \frac{2}{5} - 6 \frac{1}{3} + 2 \frac{1}{12} \cdot \frac{4}{5} = \frac{16}{15} \cdot \frac{5}{2} - \frac{19}{3} + \frac{25}{12} \cdot \frac{4}{5} = \frac{8}{3} - \frac{19}{3} + \frac{5}{3} = -\frac{6}{3} = -2$. 7) $\frac{3}{5} + 4 \frac{1}{5} \cdot (\frac{4}{21} - \frac{3}{14}) - \frac{3}{5} = 4 \frac{1}{5} \cdot (\frac{8}{42} - \frac{9}{42}) = \frac{21}{5} \cdot (-\frac{1}{42}) = -\frac{1}{10} = -0,1$. 8) $\frac{11}{14} + \frac{8}{15} : (4 - 2 \frac{26}{27}) - 1 \frac{1}{10} = \frac{11}{14} + \frac{8}{15} : (4 - \frac{80}{27}) - \frac{11}{10} = \frac{11}{14} + \frac{8}{15} : \frac{108-80}{27} - \frac{11}{10} = \frac{11}{14} + \frac{8}{15} \cdot \frac{27}{28} - \frac{11}{10} = \frac{11}{14} + \frac{18}{35} - \frac{11}{10} = \frac{55}{70} + \frac{36}{70} - \frac{77}{70} = \frac{14}{70} = \frac{1}{5} = 0,2$.

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