(3x + 7) ⋅ 2 = 32

Привет! Давай решим эти уравнения по порядку. 1) $(3x + 7) \cdot 2 = 32 \Rightarrow 3x + 7 = 16 \Rightarrow 3x = 9 \Rightarrow x = 3$ 2) $(2x - 20) : 32 = 6 \Rightarrow 2x - 20 = 192 \Rightarrow 2x = 212 \Rightarrow x = 106$ 3) $(42 + 2x) : 2 = 32 \Rightarrow 42 + 2x = 64 \Rightarrow 2x = 22 \Rightarrow x = 11$ 4) $(5x - 7) \cdot 5 = 15 \Rightarrow 5x - 7 = 3 \Rightarrow 5x = 10 \Rightarrow x = 2$ 5) $(13 - 2x) \cdot 3 = 27 \Rightarrow 13 - 2x = 9 \Rightarrow 2x = 4 \Rightarrow x = 2$ 6) $(40 - 4x) : 2 = 16 \Rightarrow 40 - 4x = 32 \Rightarrow 4x = 8 \Rightarrow x = 2$ 7) $(63 - 9x) : 3 = 15 \Rightarrow 63 - 9x = 45 \Rightarrow 9x = 18 \Rightarrow x = 2$ 8) $4(x - 3) = 12 \Rightarrow x - 3 = 3 \Rightarrow x = 6$ 9) $5(x + 5) = 45 \Rightarrow x + 5 = 9 \Rightarrow x = 4$ 10) $3(x - 7) = 9 \Rightarrow x - 7 = 3 \Rightarrow x = 10$