Допущение: некоторые примеры из Блока 3 зачеркнуты, но приведены их решения.

Решу примеры из таблицы. ### Блок 2 1) $\frac{21}{5} \cdot \frac{3}{7} = \frac{3 \cdot 3}{5 \cdot 1} = \frac{9}{5} = 1{,}8$ 2) $\frac{7}{8} : \frac{5}{6} = \frac{7}{8} \cdot \frac{6}{5} = \frac{7 \cdot 3}{4 \cdot 5} = \frac{21}{20} = 1{,}05$ 3) $\frac{3}{4} \cdot \frac{6}{5} = \frac{3 \cdot 3}{2 \cdot 5} = \frac{9}{10} = 0{,}9$ 4) $\frac{15}{2} \cdot \frac{7}{5} = \frac{3 \cdot 7}{2 \cdot 1} = \frac{21}{2} = 10{,}5$ 5) $\frac{4}{5} : \frac{2}{7} = \frac{4}{5} \cdot \frac{7}{2} = \frac{2 \cdot 7}{5 \cdot 1} = \frac{14}{5} = 2{,}8$ 6) $\frac{6}{5} : \frac{4}{11} = \frac{6}{5} \cdot \frac{11}{4} = \frac{3 \cdot 11}{5 \cdot 2} = \frac{33}{10} = 3{,}3$ 7) $\frac{3}{5} \cdot \frac{25}{4} = \frac{3 \cdot 5}{1 \cdot 4} = \frac{15}{4} = 3{,}75$ 8) $\frac{21}{5} : \frac{6}{7} = \frac{21}{5} \cdot \frac{7}{6} = \frac{7 \cdot 7}{5 \cdot 2} = \frac{49}{10} = 4{,}9$ 9) $\frac{9}{5} \cdot \frac{2}{3} = \frac{3 \cdot 2}{5 \cdot 1} = \frac{6}{5} = 1{,}2$ 10) $\frac{15}{4} \cdot \frac{6}{5} = \frac{3 \cdot 3}{2 \cdot 1} = \frac{9}{2} = 4{,}5$ ### Блок 3 1) $(\frac{9}{10} - \frac{7}{15}) \cdot 3 = (\frac{27}{30} - \frac{14}{30}) \cdot 3 = \frac{13}{30} \cdot 3 = \frac{13}{10} = 1{,}3$ 2) $(\frac{3}{4} - \frac{1}{6}) \cdot 3 = (\frac{9}{12} - \frac{2}{12}) \cdot 3 = \frac{7}{12} \cdot 3 = \frac{7}{4} = 1{,}75$ 3) $(2\frac{1}{4} - 1\frac{3}{19}) \cdot 19 = (\frac{9}{4} - \frac{22}{19}) \cdot 19 = (\frac{171 - 88}{76}) \cdot 19 = \frac{83}{76} \cdot 19 = \frac{83}{4} = 20{,}75$ 4) $({\frac{1}{13} - 2\frac{3}{4}}) \cdot 26$ (пример зачеркнут, но решим: $(\frac{4}{52} - \frac{11}{4} \cdot 13) \dots = (\frac{4 - 286}{52}) \cdot 26 = -\frac{282}{2} = -141$) 5) $(\frac{1}{5} + \frac{8}{15}) \cdot 6 = (\frac{3}{15} + \frac{8}{15}) \cdot 6 = \frac{11}{15} \cdot 6 = \frac{11 \cdot 2}{5} = \frac{22}{5} = 4{,}4$ 6) $(\frac{5}{22} - \frac{8}{11}) \cdot \frac{11}{5} = (\frac{5}{22} - \frac{16}{22}) \cdot \frac{11}{5} = -\frac{11}{22} \cdot \frac{11}{5} = -\frac{1}{2} \cdot \frac{11}{5} = -\frac{11}{10} = -1{,}1$ 7) $(\frac{9}{17} - \frac{11}{34}) \cdot \frac{17}{2} = (\frac{18}{34} - \frac{11}{34}) \cdot \frac{17}{2} = \frac{7}{34} \cdot \frac{17}{2} = \frac{7}{2 \cdot 2} = \frac{7}{4} = 1{,}75$ 8) $(\frac{17}{15} - \frac{1}{12}) \cdot \frac{20}{3} = (\frac{68}{60} - \frac{5}{60}) \cdot \frac{20}{3} = \frac{63}{60} \cdot \frac{20}{3} = \frac{21}{20} \cdot \frac{20}{3} = 7$ 9) $(\frac{10}{13} + \frac{15}{4}) \cdot \frac{26}{5} = (\frac{40 + 195}{52}) \cdot \frac{26}{5} = \frac{235}{52} \cdot \frac{26}{5} = \frac{47}{2} = 23{,}5$ 10) $(\frac{5}{26} - \frac{3}{25}) \cdot \frac{13}{2} = (\frac{125 - 78}{650}) \cdot \frac{13}{2} = \frac{47}{650} \cdot \frac{13}{2} = \frac{47}{50 \cdot 2} = \frac{47}{100} = 0{,}47$