Б) 11/17 : 9 - 2/11 · 1/9

Решение заданий: Б) $\frac{11}{17} : 9 - \frac{2}{11} \cdot \frac{1}{9} = \frac{11}{17 \cdot 9} - \frac{2}{99} = \frac{11}{153} - \frac{2}{99} = \frac{11 \cdot 11 - 2 \cdot 17}{1683} = \frac{121 - 34}{1683} = \frac{87}{1683} = \frac{29}{561}$ Д) $79 \cdot 11 - 69 : \frac{1}{11} = 869 - 69 \cdot 11 = 869 - 759 = 110$ З) $\frac{5}{12} : 0,2 + \frac{7}{12} \cdot 5 = \frac{5}{12} : \frac{1}{5} + \frac{35}{12} = \frac{25}{12} + \frac{35}{12} = \frac{60}{12} = 5$ К) $\frac{7}{8} \cdot 9 + \frac{5}{8} : \frac{1}{9} - \frac{1}{2} \cdot 9 = \frac{63}{8} + \frac{5}{8} \cdot 9 - \frac{9}{2} = \frac{63}{8} + \frac{45}{8} - \frac{36}{8} = \frac{72}{8} = 9$ Н) $\frac{5}{63} \cdot 2 \frac{3}{14} + \frac{5}{63} \cdot \frac{2}{21} + \frac{58}{63} : \frac{42}{97} = \frac{5}{63} \cdot (\frac{31}{14} + \frac{2}{21}) + \frac{58}{63} \cdot \frac{97}{42} = \frac{5}{63} \cdot (\frac{93}{42} + \frac{4}{42}) + \frac{58}{63} \cdot \frac{97}{42} = \frac{5}{63} \cdot \frac{97}{42} + \frac{58}{63} \cdot \frac{97}{42} = (\frac{5+58}{63}) \cdot \frac{97}{42} = 1 \cdot \frac{97}{42} = 2 \frac{13}{42}$ P) $\frac{3,6 \cdot 2,7 \cdot 1,5}{8,1 \cdot 0,16 \cdot 2,5} = \frac{14,58}{3,24} = 4,5$